$x^2-10x+26$ = 0

D = ${\left(-5\right)}^2-26$ = $25$ $-$ $26$ = $-1$

Da die Diskriminante D < 0 ist, hat die quadratische Gleichung keine Lösunng.

L ={}

$-12-x$ = $-x^2$ | - ( $-x^2$)

$-12-x+x^2$ = 0

sortieren

$x^2-x-12$ = 0

D = ${\left(-\frac{1}{2}\right)}^2-\left(-12\right)$ = $\frac{1}{4}$$+$ $12$ = $\frac{1}{4}$$+$ $\frac{48}{4}$ = $\frac{49}{4}$

x_1,2 = $\frac{1}{2}$ ± $\sqrt{\frac{49}{4}}$

x₁ = $\frac{1}{2}$ - $\frac{7}{2}$ = $-\frac{6}{2}$ = -3

x₂ = $\frac{1}{2}$ + $\frac{7}{2}$ = $\frac{8}{2}$ = 4

L = { $-3$; $4$}