$x^3$	=	$27$	|
$x$	=	$\sqrt[3]{27}$	= $3$

L={ $3$}

D=R\{ $-2$}

Wir multiplizieren den Nenner ${\left(x+2\right)}^2$ weg!

$\frac{4}{25}$	=	$\frac{1}{{\left(x+2\right)}^2}$	|⋅( ${\left(x+2\right)}^2$)
$\frac{4}{25}·{\left(x+2\right)}^2$	=	$\frac{1}{{\left(x+2\right)}^2}·{\left(x+2\right)}^2$
$\frac{4}{25}{\left(x+2\right)}^2$	=	$1$

$\frac{4}{25}{\left(x+2\right)}^2$	=	$1$	|⋅$\frac{25}{4}$
${\left(x+2\right)}^2$	=	$\frac{25}{4}$	|

1. Fall

2. Fall

(Alle Lösungen sind auch in der Definitionsmenge).

L={ $-\frac{9}{2}$; $\frac{1}{2}$}